#### Answer

$0.7257$

#### Work Step by Step

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{68-64}{7}\approx0.6$
Then, using the table: $P(x\leq 68)\approx P(z\leq0.6)=0.7257$

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

$0.7257$

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