Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Problem Solving - Page 762: 36b


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$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $z_{65}=\frac{65-69}{2.75}=-1.5\\z_{75}=\frac{75-69}{2.75}=2.2$ Then, using the table: $P(-1.2\leq z\geq 2.2)=0.9861-0.0668=0.9193$ The probability that 5 randomly selected men all have heights between 65 inches and 75 inches is $(0.9193)^3=0.65578$
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