## Algebra 2 (1st Edition)

Solving the equation for x, we find: $$\left(\sqrt{x-3}\right)^2=\left(x-5\right)^2 \\ x-3=x^2-10x+25 \\ x=7,\:x=4$$ Plugging this back in, we find that 7 satisfies the equation but $x=4$ does not.