Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.2 Apply Transformations to Data - 11.2 Exercises - Skill Practice - Page 753: 17


See below.

Work Step by Step

From the exercise $\overline{x}=\frac{x_1+x_2+...+x_n}{n}$. Then $\frac{ax_1+ax_2+...+ax_n}{n}=\frac{a(x_1+x_2+...+x_n)}{n}=a\frac{x_1+x_2+...+x_n}{n}=a\overline{x}$ Thus we proved what we had to.
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