Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is included:
$\bar x=\frac{8.3+8.7+9+9.3+9.9+9.9+10.2+10.4+10.7+11+11.2+11.4}{12}=10\\ Median =\frac{9.9+10.2}{2}=10.05\\Mode =9.9\\Range=11.4-8.3=3.1\\\sigma =0.96$
We will then consider the values in inches:
The new mean: $10 \times 03937=0.3937$
The new median: $10.05 \times 0.3937=3.96$
The new mode: $9.9 \times 0.3937= 3.9$
The new range: $3.1 \times 0.3937=1.22$
The new standard deviation: $0.96 \times 0.3937=0.38$
