Answer
See below
Work Step by Step
The probability of tossing a coin 30 times and getting 11 heads can be found by applying: $P(X=11)=_nC_k p^k (1-p)^{n-k}\\=_{30} C_{11} 0.5^{11}(1-0.5)^{30-11}\\=\frac{30!}{(30-11)!.11!}\times0.5 ^{30}\\=0.0508$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - 11.2 Apply Transformations to Data - 11.2 Exercises - Mixed Review - Page 755: 35
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
