Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is not included:
$\bar x=\frac{82.66+82.32+80.57+80.17+78.72+76.94+74.72+74.26}{8}\approx 78.795\\ Median =\frac{80.17+78.72}{2}=79.445\\Mode =none\\Range=82.66-74.26=8.4\\\sigma =\sqrt \frac{(82.66-78.795)^2+(82.32-78.795)^2+...+(74.26-78.795)^2}{8}=3.02$