Work Step by Step
Finding the product, we obtain: $$\left(3x\right)^3-3\left(3x\right)^2\cdot \:2y+3\cdot \:3x\left(2y\right)^2-\left(2y\right)^3\\ 27x^3-54x^2y+36xy^2-8y^3$$
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