Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 - Mixed Review - Page 723: 59


See below

Work Step by Step

$$\frac{2}{x-3}-\frac{1}{x+2}=\frac{x-5}{x+2}\\\frac{2}{x-3}=\frac{x-4}{x+2}\\x^2-7x+12=2x+4\\x^2-9x+8=0\\(x-1)(x-8)=0\\x=1 \lor x=8$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.