Answer
See below
Work Step by Step
$$\frac{2}{x-3}-\frac{1}{x+2}=\frac{x-5}{x+2}\\\frac{2}{x-3}=\frac{x-4}{x+2}\\x^2-7x+12=2x+4\\x^2-9x+8=0\\(x-1)(x-8)=0\\x=1 \lor x=8$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 - Mixed Review - Page 723: 59
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