Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.5 Find Probabilities of Independent and Dependent Events - 10.5 - Mixed Review - Page 723: 44

Answer

$$x^5-15x^4+90x^3-270x^2+405x-243$$

Work Step by Step

Using the binomial expansion theorem, we can expand the binomial without multiplying it out. Doing this, we find: $$x^5-15x^4+90x^3-270x^2+405x-243$$
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