## Algebra 2 (1st Edition)

$$\frac{2}{13}$$
We know from the equation on page 707 that: $$P(A\ or \ B) = P(A)+P(B)-P(A\ And\ B)$$ Thus, we find: $$=\frac{1}{13}+\frac{1}{13}-0=\frac{2}{13}$$