Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Finding Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Skill Practice - Page 710: 11

Answer

$0.21$

Work Step by Step

We know that $P(\text{A or B})=P(A)+P(B)-P(\text{A and B})$. Hence here: $P(\text{A and B})=P(A)+P(B)-P(\text{A or B})=0.28+0.64-0.71=0.21$
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