Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Quiz for Lessons 10.3-10.4 - Page 713: 15

Answer

See below

Work Step by Step

The probability that none of the chips are defective is: $P_1=(1-0.01)^8=(0.99)^8=0.9227$ The probability that one of the chips is defective is: $P_2=_8 C_7(1-0.01)^7\times0.01=(0.99)^8=0.0746$ The probability that at least two of the chips are defective is: $1-P_1-P_2=1-0.9227-0.0746=0.0027$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.