## Algebra 2 (1st Edition)

$\approx0.117$
The probability is $1$ minus the probability of all of them having birthdays on different days, which is: $1-\frac{365\cdot364\cdot363\cdot362\cdot361\cdot360\cdot359\cdot358\cdot357\cdot356}{365^{10}}\approx0.117$