Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Problem Solving - Page 712: 48b



Work Step by Step

The probability is $1$ minus the probability of all of them having birthdays on different days, which is: $1-\frac{365\cdot364\cdot363\cdot362\cdot361\cdot360\cdot359\cdot358\cdot357\cdot356}{365^{10}}\approx0.117$
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