Chapter 10 Counting Methods and Probability - 10.2 Use Combinations and the Binomial Theorem - 10.2 Exercises - Quiz for Lessons 10.1-10.2 - Page 697: 1

A: 676,000 permutations B: 468,000 permutations

Part A: $26\times26\times10\times10\times10=676\times1000=676,000$ For Part A, there are 676,000 permutations. Part B: $26\times25\times10\times9\times8=468,000$ For Part B, there are 468,000 permutations.