Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.2 Use Combinations and the Binomial Theorem - 10.2 Exercises - Quiz for Lessons 10.1-10.2 - Page 697: 1


A: 676,000 permutations B: 468,000 permutations

Work Step by Step

Part A: $26\times26\times10\times10\times10=676\times1000=676,000$ For Part A, there are 676,000 permutations. Part B: $26\times25\times10\times9\times8=468,000$ For Part B, there are 468,000 permutations.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.