Chapter 10 Counting Methods and Probability - 10.2 Use Combinations and the Binomial Theorem - 10.2 Exercises - Mixed Review - Page 697: 64

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The equation of the perpendicular bisector is: $$(x-a_1)^2+(y-b_1)^2=(x-a_2)^2+(y-b_2)^2$$ We have two points $A(-4,-2)\\B(6,2)$ Substitute the given values: $$(x+4)^2+(y+2)^2=(x-6)^2+(y-2)^2\\x^2+8x+16+y^2+4y+4=x^2-12x+36+y^2-4y+4\\20x+8y-20=0\\5x+2y-5=0$$