Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.1 Apply the counting Principles and Permutations - Guided Practice for Examples 1, 2, and 3 - Page 683: 2

Answer

See below.

Work Step by Step

a) Using the Fundamental Counting Principle and the example, the number of possible choices is $26\cdot26\cdot26\cdot10\cdot10\cdot10\cdot10=175760000$ b) Using the Fundamental Counting Principle and the example, the number of possible choices is $26\cdot25\cdot24\cdot10\cdot9\cdot8\cdot7=78624000$ (because each previously chosen letter or number cannot be chosen again).
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