Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.1 Apply the counting Principles and Permutations - 10.1 Exercises - Problem Solving - Page 688: 67b

Answer

$252$

Work Step by Step

Using the Fundamental Counting Principle the number of possible choices is $7\cdot9\cdot4=252$
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