Algebra 2 (1st Edition)

$$27x^3-54x^2+36x-8$$
Multiplying the equation out, we find: $$\left(3x\right)^3-3\left(3x\right)^2\cdot \:2+3\cdot \:3x\cdot \:2^2-2^3\\ 27x^3-54x^2+36x-8$$