Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - Mixed Review of Problem Solving - Lessons 1.1-1.4 - Page 33,: 8


$M=20x +7.5 y$ $x=15; y=0$ $x=12; y=8$ $x=9; y=16$

Work Step by Step

Here, we have $M=20x +7.5 y$ When $M=300$ $20x +7.5 y=300$ Now $[20x +7.5 y=300] \times 2$ We have $40 x+15 y=600$ This gives: $8x+3y=120$ or, $x=\dfrac{120-3y}{8}$ When $y=0$ then $x=\dfrac{120-3(0)}{8}=15$ When $y=8$ then $x=\dfrac{120-3(8)}{8}=12$ When $y=16$ then $x=\dfrac{120-3(16)}{8}=9$ Hence, $M=20x +7.5 y$ $x=15; y=0$ $x=12; y=8$ $x=9; y=16$
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