## Algebra 2 (1st Edition)

$M=20x +7.5 y$ $x=15; y=0$ $x=12; y=8$ $x=9; y=16$
Here, we have $M=20x +7.5 y$ When $M=300$ $20x +7.5 y=300$ Now $[20x +7.5 y=300] \times 2$ We have $40 x+15 y=600$ This gives: $8x+3y=120$ or, $x=\dfrac{120-3y}{8}$ When $y=0$ then $x=\dfrac{120-3(0)}{8}=15$ When $y=8$ then $x=\dfrac{120-3(8)}{8}=12$ When $y=16$ then $x=\dfrac{120-3(16)}{8}=9$ Hence, $M=20x +7.5 y$ $x=15; y=0$ $x=12; y=8$ $x=9; y=16$