Answer
no solutions.
Work Step by Step
$|8r+1|=3r$ implies $8r+1=3r\\1=-5r\\r=-0.2$ or $8r+1=-3r\\1=-11r\\r=\frac{-1}{11}$.
Here $r=-0.2$ and $r=\frac{-1}{11}$ are extraneous solutions. Thus we have no solutions.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 1, Equations and Inequalities - Chapter Review - Page 64: 43
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