Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - Chapter Review - Page 62: 22



Work Step by Step

$8(2n-5)=3(6n-2)\\16n-40=18n-6\\-34=2n\\n=-17$ Checking the solution: $8(2(-17)-5)=8(-34-5)=8(-39)=-312$ and $3(6(-17)-2)=3(-102-2)=3(-104)=-312$. Both sides are equal, thus $n=-17$ is indeed a solution.
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