Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.7 Solve Absolute Value Equations and Inequalities - Guided Practice for Examples 1,2, and 3 - Page 53: 6


$x=5$ or $x=-\frac{4}{3}$.

Work Step by Step

$|4x-1|=2x+9$ implies $4x-1=2x+9\\2x=10\\x=5$ or $4x-1=-2x-9\\6x=-8\\x=-\frac{4}{3}$. Here we have no extraneous solutions. Thus $x=5$ or $x=-\frac{4}{3}$.
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