## Algebra 2 (1st Edition)

$0.75\leq x\leq0.85$
Using part a). Let $x$ be the pill's weight. Then our inequality according to the exercise is: $|x-0.8|\leq0.05$. This implies $-0.05\leq x-0.8\leq0.05\\0.75\leq x\leq0.85$