## Algebra 2 (1st Edition)

$3\geq x\geq-11$ Please see image
$-8\leq-x-5\leq 6\qquad$ ...add $5$ to each part of the inequality. $-8+5\leq-x-5+5\leq 6+5\qquad$ ...simplify. $-3\leq-x\leq 11\qquad$ ...multiply each part of the inequality with $(-1)$. ...multiplying with a negative inverts the inequality signs. $-3(-1)\geq-x(-1)\geq 11(-1)\qquad$ ...simplify. $3\geq x\geq-11$ The solutions are all real numbers that are less than or equal to $3$ and greater than or equal to $-11$. Use solid dots on the number line to indicate $-11$ and $3$ are solutions.