Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.6 Solve Inequalities - 1.6 Exercises - Mixed Review - Page 47: 69

Answer

$x=-2$ The side lengths are $6$, $8$, and $5$.

Work Step by Step

We are given that the perimeter of the triangle is $19$, and the side lengths are $3x+12$, $-4x$, and $1-2x$. Thus, we can add up the side lengths to find what the perimeter is in terms of $x$. $(3x+12)+(-4x)+(1-2x)=13-3x$ Since $13-3x$ is equal to the perimeter, and the perimeter is also $19$, this must also mean that $13-3x=19$. To solve this equation, we can first subtract $13$ on both sides to isolate the variable $x$: $-3x=6$. Then, divide by $-3$ on both sides to remove the coefficient: $x=-2$. Thus, $x=-2$. To find each of the side lengths, plug $-2$ back into each side length expression and simplify. $3(-2)+12=-6+12=6$ $-4(-2)=8$ $1-2(-2)=1+4=5$
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