Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.5 Use Problem Solving Strategies and Models - 1.5 Exercises - Problem Solving - Page 39: 33

Answer

About $4.07$ in.

Work Step by Step

You are hanging fliers around a cylindrical kiosk that has a diameter of 5 feet: $5\times12\times\pi$ You want to hang 15 fliers that are 8.5 inches wide: $15\times8.5$ To know how far apart the fliers should be, use the following expression: $\frac{5\times12\times\pi-15\times8.5}{15}=\frac{60\pi -127.5}{15}\approx 4.0663\approx4.07$
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