## Algebra 2 (1st Edition)

$x \lt 4$ Please see image
$4x+9 \lt 25 \qquad$ ... add $-9$ to both sides. $4x+9-9 \lt 25-9\qquad$ ...simplify. $4x \lt 16\qquad$ ...divide both sides with $4$. $x \lt 4$ The solutions of the given inequality are all real numbers less than $4$. Smaller numbers are to the left of $4$. Use an open dot in the graph to indicate $4$ is not a solution.