#### Answer

A

#### Work Step by Step

We solve the equation for $b_1$:
$$ 2A = (b_1+b_2)h \\ \frac{2A}{h} =b_1+b_2 \\b_1= \frac{2A}{h} -b_2 $$
Option A is correct.

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

A

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