## Algebra 2 (1st Edition)

$5 \sqrt 3$
As we are given that, $d=s \sqrt 3$ The formula for $s$ can be defined as: $s=\dfrac{d}{\sqrt 3}$ Plug $15$ for $d$ Then, we have $s=\dfrac{15}{\sqrt 3}=\dfrac{5(\sqrt 3)^2}{\sqrt 3}$ or, $s=5 \sqrt 3$