Chapter 1, Equations and Inequalities - 1.4 Rewrite Equations and Formulas - 1.4 Exercises - Mixed Review - Page 32: 43

When $k=3$, $6+4k\div 2=12$

Note that due to the order of operations, $6+4k\div 2$ is equivalent to $6+\frac{4k}2$. Replace k by 3 to evaluate this expression when $k=3$: $6+4k\div 2=6+\frac{4\cdot 3}2$ $6+4k\div 2=6+\frac{12}2$ $6+4k\div 2=6+6$ $6+4k\div 2=12$