Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.3 Solve Linear Equations - 1.3 Exercises - Problem Solving - Page 23: 73b

Answer

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Work Step by Step

We have: $3c+2g=8$ For the first gap-width: $3c+2(\frac{5}{8})=8$ $3c+\frac{5}{4}=8$ $c=\frac{9}{4}$ For the second gap-width: $3(2\frac{1}{3})+2g=8$ $7+2g=8$ $g=\frac{1}{2}$ For the third gap-width: $3c+2(\frac{3}{8})=8$ $3c+\frac{3}{4}=8$ $g=\frac{29}{12}$ For the fourth gap-width: $3(2\frac{1}{2})+2g=8$ $\frac{15}{2}+2g=8$ $g=\frac{1}{4}$
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