Answer
$39$
Work Step by Step
when we substitute $n$ for 5 we get...
$12+(8-n)^{3}=12+(8-5)^{3}=12+(3)^{3}=12+(3\times3\times3)=12+(9\times3)=12+27=39$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 1, Equations and Inequalities - 1.2 Evaluate and Simplify Algebraic Expressions - 1.2 Exercises - Quiz for Lessons 1.1-1.2 - Page 16: 8
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