## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 1, Equations and Inequalities - 1.2 Evaluate and Simplify Algebraic Expressions - 1.2 Exercises - Quiz for Lessons 1.1-1.2 - Page 16: 8

#### Answer

$39$

#### Work Step by Step

when we substitute $n$ for 5 we get... $12+(8-n)^{3}=12+(8-5)^{3}=12+(3)^{3}=12+(3\times3\times3)=12+(9\times3)=12+27=39$

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