Answer
5.7 mph
Work Step by Step
We first find the speed of the elevator:
$$\frac{500\ ft}{60\ s}$$
Using unit analysis and known unit conversions, we obtain:
$$\frac{500\ ft}{60\ s}\times \frac{mi}{5280\ ft} \times\frac{3600s}{hr}=5.7mph$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 1, Equations and Inequalities - 1.1 Apply Properties of Real Numbers - 1.1 Exercises - Skill Practice - Page 7: 48
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