Answer
$10$$\frac{7}{15}$
Work Step by Step
The fractions have to be given a common denominator in $6$$\frac{2}{3}$+$3$$\frac{4}{5}$.
The least common multiple of 3 and 5 is 15. This can be found by drawing out a factor tree. Both 3 and 5 are prime to begin with, so they can be simply be multiplied together.
So, $\frac{2}{3}$$\times$$\frac{5}{5}$$=$$\frac{10}{15}$
and $\frac{4}{5}$$\times$$\frac{3}{3}$$=$$\frac{12}{15}$
Now, substitute these new fractions into the places of the old fractions in the original question.
$6$$\frac{10}{15}$+$3$$\frac{12}{15}$$=$$9$$\frac{22}{15}$
In order to get $\frac{22}{15}$ out of an improper fraction, simplify it into a mixed number. 15 goes into 22 one time and the remainder is 7. So, $\frac{22}{15}$$=$$1$$\frac{7}{15}$
Adding this answer to the whole number 9, $9+1$$\frac{7}{15}$$=10$$\frac{7}{15}$
