## Algebra 1

D) $10, 24, 26$
This question requires use of the Pythagorean Theorem ($a^{2}+b^{2}=c^{2}$). Enter the numbers from each answer into the equation. A) $12^{2}+13^{2}=17^{2}$ $144+169=289$ $313≠289$ B) $3.2^{2}+5.6^{2}=6.4^{2}$ $10.24+31.36=40.96$ $41.6≠40.96$ C) $14^{2}+20^{2}=24^{2}$ $196+400=576$ $596≠576$ D) $10^{2}+24^{2}=26^{2}$ $100+576=676$ $676=676$