Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

End of Course Assessment - Page 782: 21



Work Step by Step

We first create common denominators for the two fractions: $ \frac{8x+6}{6} - \frac{6x-3}{6}=3 $ We now can subtract the numerators of the two fractions, and then can solve: $\frac{2x+9}{6}=3 \\\\ 2x+9 = 18 \\\\ 2x=9 \\\\ x=4.5$
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