Chapter 9 - Quadratic Functions and Equations - Get Ready - Page 531: 11

Please see the graph.

The graph was made using graphing software. Three points on the line $y=2*abs(x)$ are as follows. Let $x=0$: $y=2*abs(x)$ $y=2*abs(0)$ $y=2*0$ $y=0$ $(0,0)$ Let $x=1$ $y=2*abs(x)$ $y=2*abs(1)$ $y=2*1$ $y=2$ $(1,2)$ Let $x=-1$ $y=2*abs(x)$ $y=2*abs(-1)$ $y=2*1$ $y=2$ $(-1,2)$ Thus, $(0,0), (1,2)$, and $(-1,2)$ are on the line.