Chapter 9 - Quadratic Functions and Equations - 9-8 Systems of Linear and Quadratic Equations - Practice and Problem-Solving Exercises - Page 586: 36

$(-1,6)$, $(3, 18)$ factoring

$x^2+x+6=y$ $y=2x^2-x+3$ $x^2+x+6=2x^2-x+3$ $x^2+x+6-x^2-x-6=2x^2-x+3-x^2-x-6$ $0=x^2-2x-3$ $0=(x+1)(x-3)$ $x+1=0$ $x=-1$ $x-3=0$ $x=3$ $x=-1$ $y=2x^2-x+3$ $y=2(-1)^2-(-1)+3$ $y=2*1+1+3$ $y=2+4=6$ $x=3$ $y=2x^2-x+3$ $y=2*3^2-3+3$ $y=2*9-3+3$ $y=18$