Answer
$x= .5, -1.5$
Work Step by Step
$4x^2+4x-3=0$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-4±\sqrt {4^2-4*4*-3})/2*4$
$x=(-4±\sqrt {16+48})/8$
$x=(-4±\sqrt {64})/8$
$x=(-4±8)/8$
$x=(-4+8)/8$
$x=4/8=.5$
$x=(-4-8)/8$
$x=-12/8=-1.5$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-7 Linear, Quadratic, and Exponential Models - Mixed Review - Page 580: 32
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