## Algebra 1

Published by Prentice Hall

# Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Standardized Test Prep - Page 573: 53

G

#### Work Step by Step

$1/3*x^2+1.25x+1=0$ $3*(1/3*x^2+1.25x+1=0)$ $x^2+3.75x+3=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-3.75±\sqrt {3.75^2-4*1*3})/2*1$ $x=(-3.75±\sqrt {3.75^2-4*1*3})/2*1$ $x=(-3.75±\sqrt {14.0625-12})/2$ $x=(-3.75±\sqrt {2.0625}/2$ $x=(-3.75±1.436)/2$ $x=(-3.75+1.436)/2$ $x=-2.314/2 = -1.157$ $x=(-3.75-1.436)/2$ $x=-5.186/2 = -2.593$

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