Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Lesson Check - Page 571: 1

$x = -4, 1/3$

$-3x^2-11x+4=0$ $x = (-b)±\sqrt {(b^2-4*a*c})/2*a$ $x = (-(-11)±\sqrt {(-11)^2-4*-3*4})/2*-3$ $x = (11±\sqrt {121+48})/-6$ $x = (11±\sqrt {169})/-6$ $x = (11+13)/-6$ or $x = (11-13)/-6$ $x = (11+13)/-6$ $x = 24/-6 = -4$ $x = (11-13)/-6$ $x = -2/-6 = 1/3$