Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Mixed Review - Page 566: 63



Work Step by Step

Given: $y^8(y^{-7})^{-3}$ Firstly multiply the power exponents and then add the exponents of the common base term. $y^8(y^{-7})^{-3}=y^8(y^{-7 \times {-3}})$ $=y^{8+21}$ $=y^{29}$
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