## Algebra 1

a) $k^2-3k=304$ $k^2-3k+(3/2)^2=304+(3/2)^2$ $k^2-3k+9/4 = 304+ 9/4$ $k^2-3k+9/4 = 1216/4+9/4$ $(k-3/2)^2 = 1225/4$ $\sqrt {(k-3/2)^2)} = \sqrt {1225/4}$ $(k-3/2) = ±35/2$ $k-3/2 = 35/2$ $k=38/2$ $k=19$ $k-3/2 = -35/2$ $k = -32/2$ $k=-16$ b) $t^2-6t+16=0$ $b^2-4ac$ $(-6)-4*1*16$ $36-64$ $-28$ There are no solutions for this equation (since the discriminant is negative).