Answer
$x= -2, -1, 2$
Work Step by Step
$x^3+x^2-4x-4=0$
$x^2(x+1)-4(x+1)=0$
$(x^2-4)(x+1)=0$
$(x-2)(x+2)(x+1)=0$
$x-2=0$
$x-2+2=0$
$x=2$
$x+2=0$
$x+2-2=0$
$x=-2$
$x+1=0$
$x+1-1=0$
$x=-1$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 559: 44
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