Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Mixed Review: 53

Answer

$\pm12$

Work Step by Step

$\pm\sqrt {144}$ According to the textbook, a number, $a$, is a square root of another number, $b$, if $a^2=b$. Since $12^2=144$, $12$ is a square root of $144$. Given this, we can deduce that: $\pm\sqrt {144}=\pm12$
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