Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-1 Quadratic Graphs and Their Properties - Practice and Problem-Solving Exercises: 26

Answer

$\approx$1.581 seconds

Work Step by Step

The question asks for when the orange hits the water. The variable, $h$, is the height of the orange. Therefore, we must solve for when $h$ is equal to 0. $ 0 = -16t^{2}+40$ $-40 = -16t^{2}$ $\frac{40}{16} = t^{2}$ $\frac{5}{2} = t^{2}$ $\sqrt \frac{5}{2} = t$ $t \approx 1.581$ seconds
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