Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 521: 43

Answer

$(5g^{2}+4h)(6g^{3}-7h^{2})$

Work Step by Step

$30g^{5} + 24g^{3}h - 35h2^{5}g^{2} - 28h^{3}$ Group the first two and last two terms together. $(30g^{5} + 24g^{3}h) (- 35h2^{5}g^{2} - 28h^{3})$ Factor out the GCF from the first two and last two terms $6g^{3}(5g^{2}+4h) - 7h^{2}(5g^{2}+4h)$ Take the common $(5g^{2}+4h)$ and factor it out $(5g^{2}+4h)(6g^{3}-7h^{2})$
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