Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Standardized Test Prep - Page 510: 52


$7x^{2}$ - 61x - 18 = (7x+2)(x-9)

Work Step by Step

$7x^{2}$ - 61x - 18 = (7x+2)(x-p) Given the rule, we know that the last term of a polynomial is a product of the last term in each parenthesis. To get the second term we divide the last term of the polynomial by the last term of the first parenthesis. $\frac{-18}{2}$ = -9 (x-9) Thus, $7x^{2}$ - 61x - 18 = (7x+2)(x-9)
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