## Algebra 1

Given the polynomial $x^{2}$ + 15x + 54 *** We break of the middle term into two factors that add to give +15 and multiply to give +54. The two numbers are +6 and +9. $x^{2}$ + 9x + 6x + 54 We take the GCD of the first two and the GDC of the last two terms. x(x+9) +6(x+9) We take (x+9) and factor it out which gives us. (x+9)(x+6)